$CH_3-CH_2-CH(Cl)_2$ $\xrightarrow[{[Excess]}]{{NaNH_2}} P$ $\xrightarrow{{CH_3Cl}} Q$,$Q$ will be

  • A
    $CH_3-CH_2-C \equiv CH$
  • B
    $CH_3-CH_2-C \equiv C-CH_3$
  • C
    $CH_3-CH_2-CH_2-CH_2-Cl$
  • D
    $CH_2=CH-CH=CH_2$

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In order to complete the reaction $1-Pentyne$ $\xrightarrow{a} 4-Octyne$ $\xrightarrow{b} cis-4-Octene$,$a$ and $b$ will be:
$A) NaNH_2; CH_3CH_2CH_2Br : H_2, (1 \ mole) \text{ Lindlar catalyst}$
$B) NaNH_2; CH_3CH_2CH_2Br : H_2, (2 \ moles) \text{ Pd or Ni}$
$C) NaNH_2; CH_3CH_2CH_2Br : H_2, (1 \ mole) \text{ Pd or Ni}$
$D) NaNH_2; CH_3CH_2CH_2Br : BH_3, H_2O_2, OH^-$

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How many carbons are in the simplest alkyne having two side chains?

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