(A) The hydrolysis of silicon tetrachloride $(SiCl_4)$ proceeds as follows: $SiCl_4 + 4H_2O \rightarrow Si(OH)_4 + 4HCl$. Thus,$Si(OH)_4$ (orthosilici

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(A) The hydrolysis of silicon tetrachloride $(SiCl_4)$ proceeds as follows: $SiCl_4 + 4H_2O \rightarrow Si(OH)_4 + 4HCl$. Thus,$Si(OH)_4$ (orthosilicic acid) is indeed the product formed at the end of the hydrolysis of $SiCl_4$. Therefore,the statement is $True$.

Class 11 Chemistry p-Block Elements (Class 11)Carbon family

Easy

$Si(OH)_4$ acid is produced at the end of hydrolysis of $SiCl_4$. Is this statement true or false?

A
True
B
False
C
Cannot be determined
D
None of the above

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Class 11

Chemistry Questions

Chapter

p-Block Elements (Class 11)

Subtopic

Carbon family

Match List-$I$ with List-$II$.

List-$I$ (Si-Compounds) List-$II$ (Si-Polymeric/other products)

$A$. $(CH_3)_4 Si$ $I$. Chain silicone

$B$. $(CH_3) Si(OH)_3$ $II$. Dimeric silicone

$C$. $(CH_3)_2 Si(OH)_2$ $III$. Silane

$D$. $(CH_3)_3 Si(OH)$ $IV$. $2D$-Silicone

Choose the correct answer from the options given below:

List-$I$ (Si-Compounds)	List-$II$ (Si-Polymeric/other products)
$A$. $(CH_3)_4 Si$	$I$. Chain silicone
$B$. $(CH_3) Si(OH)_3$	$II$. Dimeric silicone
$C$. $(CH_3)_2 Si(OH)_2$	$III$. Silane
$D$. $(CH_3)_3 Si(OH)$	$IV$. $2D$-Silicone