In a plant,the genotype of the F_1 generation | vedclass

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(A) The given genotype is $AABbCC$. Self-pollination means the cross is $AABbCC 	imes AABbCC$. We can analyze the inheritance of each gene pair indep

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$3 : 1$

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(A) The given genotype is $AABbCC$. Self-pollination means the cross is $AABbCC 	imes AABbCC$. We can analyze the inheritance of each gene pair independently: $1$. For gene $A$: $AA 	imes AA$ results in all $AA$ offspring (monomorphic). $2$. For gene $B$: $Bb 	imes Bb$ results in a phenotypic ratio of $3:1$ (dominant:recessive). $3$. For gene $C$: $CC 	imes CC$ results in all $CC$ offspring (monomorphic). Since genes $A$ and $C$ are homozygous,they do not contribute to phenotypic variation. Therefore,the overall phenotypic ratio is determined solely by the $Bb$ gene pair,which is $3:1$.

$S.No$	Cross	Result
$I.$ Strain $1 \times gg$	All wild type
$II.$ Strain $2 \times gg$	$1$ wild type $: 1$ ebony
$III.$ Strain $3 \times gg$	All ebony
$IV.$ Strain $4 \times Gg$	$3$ wild type $: 1$ ebony

In a plant,the genotype of the $F_1$ generation is $AABbCC$. Upon self-pollination of this plant,the phenotypic ratio in the $F_2$ generation will be:

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