A human male is heterozygous for autosomal ge | vedclass

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Question

(A) The genotype of the male is $AaBbX^hY$. Since genes $A$ and $B$ are autosomal and heterozygous,the possible gametes for these alleles are $AB, Ab,

Vedclass · Accepted Answer

$1/8$

Vedclass · Answer

(A) The genotype of the male is $AaBbX^hY$. Since genes $A$ and $B$ are autosomal and heterozygous,the possible gametes for these alleles are $AB, Ab, aB, ab$ with a probability of $1/4$ each. The male is hemizygous for the $hemophilia$ gene $(X^hY)$,meaning he carries the $X^h$ chromosome and the $Y$ chromosome. The probability of a sperm receiving the $X^h$ chromosome is $1/2$,and the probability of receiving the $Y$ chromosome is $1/2$. For a sperm to be $abh$,it must contain the $a$ allele,the $b$ allele,and the $h$ allele (which is carried on the $X^h$ chromosome). The probability of getting $ab$ from the autosomal genes is $1/4$. The probability of getting the $X^h$ chromosome is $1/2$. Therefore,the total probability is $1/4 	imes 1/2 = 1/8$.

Column-$I$	Column-$II$
$(p)$ Mendel	$(i)$ Chromosomal theory of Inheritance
$(q)$ Morgan	$(ii)$ Recombination map
$(r)$ Alfred Sturtevant	$(iii)$ Linkage
$(s)$ Sutton	$(iv)$ Law of Segregation

$A$ human male is heterozygous for autosomal genes $A$ and $B$ and is also hemizygous for the $hemophilia$ gene. What proportion of his sperm will be $abh$?

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Match the following and choose the correct option:
Column-$I$ Column-$II$
$(p)$ Mendel $(i)$ Chromosomal theory of Inheritance
$(q)$ Morgan $(ii)$ Recombination map
$(r)$ Alfred Sturtevant $(iii)$ Linkage
$(s)$ Sutton $(iv)$ Law of Segregation

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