In Mendel's pea plants,round seeds (RR) are d | vedclass

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(D) $1$. The cross between $RRYY$ (round,yellow) and $rryy$ (wrinkled,green) is a dihybrid cross.$2$. The $F_1$ generation will be $RrYy$ (round,yello

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Round seeds and yellow cotyledons,and wrinkled seeds and green cotyledons

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(D) $1$. The cross between $RRYY$ (round,yellow) and $rryy$ (wrinkled,green) is a dihybrid cross.$2$. The $F_1$ generation will be $RrYy$ (round,yellow).$3$. In the $F_2$ generation,selfing of $F_1$ $(RrYy 	imes RrYy)$ results in four phenotypes in the ratio $9:3:3:1$.$4$. The four phenotypes are: Round-Yellow $(9)$,Round-Green $(3)$,Wrinkled-Yellow $(3)$,and Wrinkled-Green $(1)$.$5$. The question asks for the phenotypic expression in the $F_2$ generation. The possible phenotypes are Round-Yellow,Round-Green,Wrinkled-Yellow,and Wrinkled-Green.

In Mendel's pea plants,round seeds $(RR)$ are dominant over wrinkled seeds $(rr)$,and yellow cotyledons $(YY)$ are dominant over green cotyledons $(yy)$. What will be the phenotypic ratio in the $F_2$ generation of a cross between $RRYY$ and $rryy$?

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