A man whose father was colorblind marries a w | vedclass

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(A) Colorblindness is an $X$-linked recessive trait.$1$. The man's father was colorblind,so the man must have received his $Y$ chromosome from his fat

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(A) Colorblindness is an $X$-linked recessive trait.$1$. The man's father was colorblind,so the man must have received his $Y$ chromosome from his father and his $X$ chromosome from his mother. Since he is a male,his genotype is $X^CY$ (where $X^C$ is the colorblind allele). However,the man himself is normal,so his genotype is $XY$.$2$. The woman has a colorblind mother $(X^CX^C)$ and a normal father $(XY)$. She must have inherited one $X^C$ from her mother and one $X$ from her father. Thus,her genotype is $X^CX$.$3$. The cross is $XY$ (man) $	imes$ $X^CX$ (woman).$4$. The possible genotypes of the offspring are: $XX^C$ (carrier daughter),$XX$ (normal daughter),$X^CY$ (colorblind son),and $XY$ (normal son).$5$. Among the male children,the genotypes are $X^CY$ and $XY$. The probability of a male child being colorblind is $1/2$ or $50\%$.

$A$ man whose father was colorblind marries a woman who has a colorblind mother and a normal father. What is the percentage probability of their male children being colorblind (in $\%$)?

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