Two cells $A$ and $B$ are placed in contact. Cell $A$ has an osmotic pressure of $10 \text{ atm}$,turgor pressure of $7 \text{ atm}$,and $DPD$ of $3 \text{ atm}$. Cell $B$ has an osmotic pressure of $8 \text{ atm}$,turgor pressure of $3 \text{ atm}$,and $DPD$ of $5 \text{ atm}$. What will be the result?

  • A
    No movement of water occurs.
  • B
    Equilibrium is established between the two.
  • C
    Water moves from cell $A$ to cell $B$.
  • D
    Water moves from cell $B$ to cell $A$.

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Similar Questions

The osmotic parameter determining the flow of water from one cell to another is:

Two cells $A$ and $B$ are contiguous. Cell-$A$ has osmotic pressure-$10$ atm,turgor pressure-$7$ atm and diffusion pressure deficit-$3$ atm. Cell-$B$ has osmotic pressure-$8$ atm,turgor pressure-$3$ atm and diffusion pressure deficit-$5$ atm. The result will be

Match Column-$I$ with Column-$II$.
Column-$I$Column-$II$
$i$. Turgid cell$a$. $T.P. = 0$
$ii$. Pure water$b$. $D.P.D. = 0$
$iii$. Flaccid cell$c$. $\Psi_w = 0$

Under given suitable conditions,the $DPD$ will be more than $OP$.

If a cell $A$ with $DPD$ $4 \, \text{bars}$ is connected to cells $B$, $C$, and $D$ whose $OP$ and $TP$ are respectively $(4, 4)$, $(10, 5)$, and $(7, 3) \, \text{bars}$, the flow of water will be:

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