PCl_{5} + P_{4}O_{10} xrightarrow{Delta } X. | vedclass

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Question

(B) The reaction between $PCl_{5}$ and $P_{4}O_{10}$ is given by: $6 PCl_{5} + P_{4}O_{10} \xrightarrow{\Delta } 10 POCl_{3}$. Thus,the compound $(X)$

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) The reaction between $PCl_{5}$ and $P_{4}O_{10}$ is given by: $6 PCl_{5} + P_{4}O_{10} \xrightarrow{\Delta } 10 POCl_{3}$. Thus,the compound $(X)$ is $POCl_{3}$. The hydrolysis reaction of $POCl_{3}$ is: $POCl_{3} + 3 H_{2}O \longrightarrow H_{3}PO_{4} + 3 HCl$. From the stoichiometry of the reaction,$1 	ext{ mole}$ of $POCl_{3}$ produces $1 	ext{ mole}$ of phosphoric acid $(H_{3}PO_{4})$,which is an oxyacid. Therefore,the correct answer is $1$.

$PCl_{5} + P_{4}O_{10} \xrightarrow{\Delta } X$. The product $(X)$ is an oxygen-containing compound. How many moles of an oxyacid are formed on the complete hydrolysis of $1 \text{ mole}$ of $(X)$?

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