$2\,g$ of benzoic acid $(C_6H_5COOH)$ dissolved in $25\,g$ of benzene shows a depression in freezing point equal to $1.62\,K$. The molal depression constant $(K_f)$ for benzene is $4.9\,K\,kg\,mol^{-1}$. What is the percentage degree of association of the acid?

  • A
    $99.2$
  • B
    $95$
  • C
    $90$
  • D
    $0.8$

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When $12.2 \ g$ of benzoic acid is dissolved in $100 \ g$ of benzene, the freezing point of the solution is found to be $-0.93^{\circ} C$ $(K_{f}(\text{benzene}) = 5.12 \ K \ kg \ mol^{-1})$. The number $(n)$ of benzoic acid molecules associated (assuming $100 \ \%$ association) is ........ .

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