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(C) The potential at a distance $r$ from the center is given by $V = -\int_{\infty}^{r} E \cdot dr$.For $r > b$,the electric field is $E = \frac{Q}{4\

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$\frac{Q}{{4\pi {\varepsilon _0}b}}$

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(C) The potential at a distance $r$ from the center is given by $V = -\int_{\infty}^{r} E \cdot dr$.For $r > b$,the electric field is $E = \frac{Q}{4\pi \varepsilon_0 r^2}$.For $a The potential at the surface of the dielectric (radius $b$) is the work done in bringing a unit positive charge from infinity to $b$.$V_b = \int_{b}^{\infty} E_{out} dr = \int_{b}^{\infty} \frac{Q}{4\pi \varepsilon_0 r^2} dr = \frac{Q}{4\pi \varepsilon_0 b}$.Thus,the potential at the outer surface of the dielectric is $\frac{Q}{4\pi \varepsilon_0 b}$.

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