(A) During electrolysis,the ion with the higher standard reduction potential $(E^{\circ})$ is reduced first at the cathode.Comparing the given values:

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(A) During electrolysis,the ion with the higher standard reduction potential $(E^{\circ})$ is reduced first at the cathode.Comparing the given values:$E^{\circ}_{A^{2+}/A} = 0.8 \ V$$E^{\circ}_{B^{3+}/B} = 0.6 \ V$Since $0.8 \ V > 0.6 \ V$,the ion $A^{2+}_{(aq.)}$ has a higher reduction potential.Therefore,$A^{2+}_{(aq.)}$ will be deposited first at the cathode.

Class 12 Chemistry Electrochemistry Electrochemical cells

Medium

$A^{2+}_{(aq.)} + 2e^- \to A_{(s)}$ ; $E^{\circ} = 0.8 \ V$
$B^{3+}_{(aq.)} + 3e^- \to B_{(s)}$ ; $E^{\circ} = 0.6 \ V$
Using the above information,find the ion which will be deposited first at the cathode if a solution containing $A^{2+}_{(aq.)}$ and $B^{3+}_{(aq.)}$ is electrolysed.

A
$A^{2+}_{(aq.)}$
B
$B^{3+}_{(aq.)}$
C
$H^{+}_{(aq.)}$
D
$OH^{-}_{(aq.)}$

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For the reaction $Cu^{2+}_{(aq)} + Fe_{(s)} \rightleftharpoons Fe^{2+}_{(aq)} + Cu_{(s)}$,calculate $\Delta G^o$ in Joules.
Given: $E^o_{Cu^{2+}/Cu} = +0.34 \ V$,$E^o_{Fe^{2+}/Fe} = -0.44 \ V$.

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$E^{\circ}_{Cu^{2+}|Cu} = +0.34 \ V$
$E^{\circ}_{Zn^{2+}|Zn} = -0.76 \ V$
Identify the incorrect statement from the options below for the above cell.

MediumJEE MAIN 2020

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In the cell represented $Pb_{(s)}|Pb_{(1 \ M)}^{2+} || Ag_{(1 \ M)}^{+}|Ag_{(s)}$,the reducing agent is

MediumMHT CET 2016

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Derive the relation between the dissociation constant $K_a$ and the limiting molar conductivity $\Lambda_m^o$ for a solution of a weak electrolyte.

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Draw the diagram of a galvanic cell and indicate the direction of flow of electrons and current for the cell constructed using $Al|Al^{3+}$ and $Ag^{+}|Ag$ half-cells,given $E^o_{Al^{3+}|Al} = -1.66 \ V$ and $E^o_{Ag^{+}|Ag} = 0.80 \ V$.

Medium

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$A^{2+}_{(aq.)} + 2e^- \to A_{(s)}$ ; $E^{\circ} = 0.8 \ V$$B^{3+}_{(aq.)} + 3e^- \to B_{(s)}$ ; $E^{\circ} = 0.6 \ V$Using the above information,find the ion which will be deposited first at the cathode if a solution containing $A^{2+}_{(aq.)}$ and $B^{3+}_{(aq.)}$ is electrolysed.

Similar Questions

For the reaction $Cu^{2+}_{(aq)} + Fe_{(s)} \rightleftharpoons Fe^{2+}_{(aq)} + Cu_{(s)}$,calculate $\Delta G^o$ in Joules.Given: $E^o_{Cu^{2+}/Cu} = +0.34 \ V$,$E^o_{Fe^{2+}/Fe} = -0.44 \ V$.

$E^{\circ}_{Cu^{2+}|Cu} = +0.34 \ V$$E^{\circ}_{Zn^{2+}|Zn} = -0.76 \ V$Identify the incorrect statement from the options below for the above cell.

In the cell represented $Pb_{(s)}|Pb_{(1 \ M)}^{2+} || Ag_{(1 \ M)}^{+}|Ag_{(s)}$,the reducing agent is

Derive the relation between the dissociation constant $K_a$ and the limiting molar conductivity $\Lambda_m^o$ for a solution of a weak electrolyte.

Draw the diagram of a galvanic cell and indicate the direction of flow of electrons and current for the cell constructed using $Al|Al^{3+}$ and $Ag^{+}|Ag$ half-cells,given $E^o_{Al^{3+}|Al} = -1.66 \ V$ and $E^o_{Ag^{+}|Ag} = 0.80 \ V$.

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$A^{2+}_{(aq.)} + 2e^- \to A_{(s)}$ ; $E^{\circ} = 0.8 \ V$
$B^{3+}_{(aq.)} + 3e^- \to B_{(s)}$ ; $E^{\circ} = 0.6 \ V$
Using the above information,find the ion which will be deposited first at the cathode if a solution containing $A^{2+}_{(aq.)}$ and $B^{3+}_{(aq.)}$ is electrolysed.

For the reaction $Cu^{2+}_{(aq)} + Fe_{(s)} \rightleftharpoons Fe^{2+}_{(aq)} + Cu_{(s)}$,calculate $\Delta G^o$ in Joules.
Given: $E^o_{Cu^{2+}/Cu} = +0.34 \ V$,$E^o_{Fe^{2+}/Fe} = -0.44 \ V$.

$E^{\circ}_{Cu^{2+}|Cu} = +0.34 \ V$
$E^{\circ}_{Zn^{2+}|Zn} = -0.76 \ V$
Identify the incorrect statement from the options below for the above cell.