A and B are two metallic rings placed at oppo | vedclass

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(B) According to the right-hand thumb rule,the magnetic field produced by the current-carrying wire is directed out of the paper on the left side (whe

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anticlockwise in $A$ and clockwise in $B$

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(B) According to the right-hand thumb rule,the magnetic field produced by the current-carrying wire is directed out of the paper on the left side (where ring $A$ is placed) and into the paper on the right side (where ring $B$ is placed).As the current in the wire decreases,the magnetic flux through both rings decreases.According to Lenz's Law,the induced current in the rings will oppose this decrease in magnetic flux by creating its own magnetic field in the same direction as the original field.For ring $A$,the original field is out of the paper. To support this,the induced current must be anticlockwise.For ring $B$,the original field is into the paper. To support this,the induced current must be clockwise.Therefore,the induced current is anticlockwise in $A$ and clockwise in $B$.

$A$ and $B$ are two metallic rings placed at opposite sides of an infinitely long straight conducting wire as shown. If the current in the wire is slowly decreased,the direction of the induced current will be:

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