CH_3-C(CH_3)_2-CH=CH_2 xrightarrow[H_2O_2/OH^ | vedclass

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(C) The reaction is Hydroboration-Oxidation. It involves the anti-Markovnikov addition of $H_2O$ across the double bond without rearrangement. $CH_3-C

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Optically inactive $1^o$ alcohol

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(C) The reaction is Hydroboration-Oxidation. It involves the anti-Markovnikov addition of $H_2O$ across the double bond without rearrangement. $CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[H_2O_2/OH^{-}]{B_2H_6/THF} CH_3-C(CH_3)_2-CH_2-CH_2OH$ The product is $3,3-	ext{dimethylbutan-1-ol}$,which is a primary $(1^o)$ alcohol and lacks a chiral center,making it optically inactive.

$CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[H_2O_2/OH^{-}]{B_2H_6/THF} (Z)$ Major product

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The conversion$(s)$ that can be carried out by bromine in carbon tetrachloride $(CCl_4)$ solvent is/are:

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Which of the following is Baeyer's reagent?

Product '$A$' and '$B$' are respectively:
$CH_3-C(CH_3)=CH-C_6H_5 \xrightarrow{HBr/Peroxide} A$
$CH_3-C(CH_3)=CH-C_6H_5 \xrightarrow{HBr} B$

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