NH_3 + O_2 xrightarrow[500 K]{Pt} A + H_2OA | vedclass

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(B) The reactions represent the $Ostwald's \ process$ for the manufacture of $HNO_3$.$1$. $4NH_3 + 5O_2 \xrightarrow[500 \ K]{Pt} 4NO + 6H_2O$. Thus,$

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$NO, NO_2$ and $HNO_3$

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(B) The reactions represent the $Ostwald's \ process$ for the manufacture of $HNO_3$.$1$. $4NH_3 + 5O_2 \xrightarrow[500 \ K]{Pt} 4NO + 6H_2O$. Thus,$A = NO$.$2$. $2NO + O_2 	o 2NO_2$. Thus,$B = NO_2$.$3$. $3NO_2 + H_2O 	o 2HNO_3 + NO$. Thus,$C = HNO_3$.Therefore,$A, B$ and $C$ are $NO, NO_2$ and $HNO_3$ respectively.

$NH_3 + O_2 \xrightarrow[500 \ K]{Pt} A + H_2O$
$A + O_2 \to B$; $B + H_2O \to C + A$
$A, B$ and $C$ respectively are

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$NH_3 + O_2 \xrightarrow[500 \ K]{Pt} A + H_2O$$A + O_2 \to B$; $B + H_2O \to C + A$$A, B$ and $C$ respectively are