BF_3 on hydrolysis forms: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The hydrolysis of $BF_3$ occurs in two steps:$1$. $BF_3$ reacts with water to form boric acid $(H_3BO_3)$ and hydrogen fluoride $(HF)$:$BF_3 + 3 H

Vedclass · Accepted Answer

Both $(A)$ and $(B)$

Vedclass · Answer

(C) The hydrolysis of $BF_3$ occurs in two steps:$1$. $BF_3$ reacts with water to form boric acid $(H_3BO_3)$ and hydrogen fluoride $(HF)$:$BF_3 + 3 H_2O \rightarrow B(OH)_3 + 3 HF$$2$. The $HF$ produced reacts with excess $BF_3$ to form fluoroboric acid $(HBF_4)$:$3 HF + 3 BF_3 \rightarrow 3 H[BF_4]$Combining these,the overall reaction is:$4 BF_3 + 3 H_2O \rightarrow B(OH)_3 + 3 H[BF_4]$Thus,both $H_3BO_3$ and $HBF_4$ are formed.

$BF_3$ on hydrolysis forms:

Similar Questions

Aluminium reacts with $NaOH$ and forms compound '$X$'. If the coordination number of aluminium in '$X$' is $6$, the correct formula of $X$ is:

Which one of the following statements is not correct?

What are electron-deficient compounds? Are $BCl_3$ and $SiCl_4$ electron-deficient species?

Draw the structure of diborene $(B_2H_4)$.

What is the correct formula for Borazole?

Vedclass Test Series

Exam Paper Generator

Online Exam Module