The reactant is 4-hydroxy-3-methylbenzenesulf | vedclass

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(D) The starting material is $4-hydroxy-3-methylbenzenesulfonic acid$.In the presence of $Br_2$ and $H_2O$,the $-OH$ group activates the ring towards

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(D) The starting material is $4-hydroxy-3-methylbenzenesulfonic acid$.In the presence of $Br_2$ and $H_2O$,the $-OH$ group activates the ring towards electrophilic substitution at the ortho positions.The $-SO_3H$ group at the para position is a good leaving group and is displaced by the bromine electrophile.Since the ortho positions relative to the $-OH$ group are at $C-2$ and $C-6$,and the $C-3$ position is already occupied by a $-CH_3$ group,bromine will substitute at the $C-2$ position and the $C-4$ position (replacing the $-SO_3H$ group).Thus,the product is $2,4-dibromo-6-methylphenol$ (or $2,6-dibromo-4-methylphenol$ depending on numbering,but based on the provided options,the structure corresponds to $2,4-dibromo-6-methylphenol$).

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