The product of the following reaction is:
$Ph-CO-CH_3 \xrightarrow[{(ii)\,\Delta }]{{(i)\,aq.\,K_2CO_3}}$ Product
$Ph-CO-CH_3 \xrightarrow[{(ii)\,\Delta }]{{(i)\,aq.\,K_2CO_3}}$ Product
- A$Ph-CH(OH)-CH_3$
- B$Ph-CO-CH=C(CH_3)-Ph$
- C$Ph-CO-CH_2-CH_2-CO-Ph$
- D$Ph-CO-CH_2-CH(OH)-Ph$
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Similar Questions
Match the compounds in Column-$I$ with their respective intermolecular attraction forces in Column-$II$.
Column-$I$ (Compound) Column-$II$ (Attraction Forces) $A$. Aldehyde $i$. Intermolecular hydrogen bond formed in $ROH$ between $O^{\delta -}$ of one molecule and $H^{\delta +}$ of another molecule. $B$. Ketone $ii$. Dipole-dipole forces between $C^{\delta +}$ of one molecule and $O^{\delta -}$ of another molecule. $C$. Alcohol $iii$. van der Waals forces $D$. Alkane $iv$. Ionic forces
| Column-$I$ (Compound) | Column-$II$ (Attraction Forces) |
|---|---|
| $A$. Aldehyde | $i$. Intermolecular hydrogen bond formed in $ROH$ between $O^{\delta -}$ of one molecule and $H^{\delta +}$ of another molecule. |
| $B$. Ketone | $ii$. Dipole-dipole forces between $C^{\delta +}$ of one molecule and $O^{\delta -}$ of another molecule. |
| $C$. Alcohol | $iii$. van der Waals forces |
| $D$. Alkane | $iv$. Ionic forces |
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The final product formed when acetaldehyde is reduced with sodium and alcohol is
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