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(B) The reaction of $1$-fluoro-$1$-methylcyclohexane with alcoholic $KOH$ proceeds via an $E2$ elimination mechanism.In cases involving alkyl fluoride

Vedclass · Accepted Answer

Methylenecyclohexane

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(B) The reaction of $1$-fluoro-$1$-methylcyclohexane with alcoholic $KOH$ proceeds via an $E2$ elimination mechanism.In cases involving alkyl fluorides,the transition state has significant carbanion character due to the high electronegativity of the fluorine atom.According to the Hofmann rule,the less substituted alkene is formed as the major product because the transition state leading to it is more stable due to less steric hindrance and the electronic effects of the fluorine leaving group.Therefore,the major product is methylenecyclohexane.

Identify the major product for the following reaction:
$1$-fluoro-$1$-methylcyclohexane $\xrightarrow[\Delta]{Alc. KOH}$ ?

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Identify the major product for the following reaction: $1$-fluoro-$1$-methylcyclohexane $\xrightarrow[\Delta]{Alc. KOH}$ ?