C_6H_5-C equiv C-CH_3 xrightarrow[H_2SO_4]{Hg | vedclass

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(A) The hydration of an alkyne in the presence of $HgSO_4$ and $H_2SO_4$ (Kucherov reaction) follows Markovnikov's rule.In the reaction of $C_6H_5-C \

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Propiophenone

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(A) The hydration of an alkyne in the presence of $HgSO_4$ and $H_2SO_4$ (Kucherov reaction) follows Markovnikov's rule.In the reaction of $C_6H_5-C \equiv C-CH_3$,the carbocation formed at the carbon adjacent to the phenyl ring $(C_6H_5-C^+=CH-CH_3)$ is more stable due to resonance with the benzene ring.Thus,the $-OH$ group adds to that carbon,forming an enol $C_6H_5-C(OH)=CH-CH_3$.This enol undergoes tautomerization to form the more stable ketone,which is $C_6H_5-CO-CH_2-CH_3$ (Propiophenone).

$C_6H_5-C \equiv C-CH_3 \xrightarrow[H_2SO_4]{HgSO_4, H_2O} A$. The major product $(A)$ is:

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