In the balanced chemical equation MnO_4^- + B | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The oxidation half-reaction is: $Br^- + 6OH^- 	o BrO_3^- + 3H_2O + 6e^-$The reduction half-reaction is: $MnO_4^- + 2H_2O + 3e^- 	o MnO_2 + 4OH^-

Vedclass · Accepted Answer

$2, 1, 2$

Vedclass · Answer

(C) The oxidation half-reaction is: $Br^- + 6OH^- 	o BrO_3^- + 3H_2O + 6e^-$The reduction half-reaction is: $MnO_4^- + 2H_2O + 3e^- 	o MnO_2 + 4OH^-$To balance the electrons,multiply the reduction half-reaction by $2$:$2MnO_4^- + 4H_2O + 6e^- 	o 2MnO_2 + 8OH^-$Adding the two half-reactions:$2MnO_4^- + Br^- + 4H_2O 	o 2MnO_2 + BrO_3^- + 3H_2O + 2OH^-$Simplifying the water molecules:$2MnO_4^- + Br^- + H_2O 	o 2MnO_2 + BrO_3^- + 2OH^-$The coefficients of $MnO_4^-$,$BrO_3^-$,and $OH^-$ are $2, 1, 2$ respectively.

In the balanced chemical equation $MnO_4^- + Br^- + H_2O \to MnO_2 + BrO_3^- + OH^-$,the coefficients of $MnO_4^-$,$BrO_3^-$,and $OH^-$ are respectively:

Similar Questions

In balancing the half-reaction $S_2O_3^{2-} \to S_{(s)}$,the number of electrons that must be added is:

In a balanced equation $H_2SO_4 + x \ HI \to H_2S + y \ I_2 + z \ H_2O$,the values of $x, y, z$ are

Equivalent mass of the oxidizing agent in the reaction $SO_2 + 2H_2S \to 3S + 2H_2O$ is

What is the number of moles of electrons gained by one mole of oxidizing agent in the following redox reaction?
$Zn_{(s)} + 2HCl_{(aq)} \longrightarrow ZnCl_2(aq) + H_2(g)$

$2 IO_3^- + x I^- + 12 H^+ \rightarrow 6 I_2 + 6 H_2 O$. What is the value of $x$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module