Cu^{2+} will have the following electronic co | vedclass

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(C) The atomic number of Copper $(Cu)$ is $29$.The ground state electronic configuration of $Cu$ is $[Ar] 3d^{10} 4s^1$,which is $1s^2 2s^2 2p^6 3s^2

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$1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^9$

Vedclass · Answer

(C) The atomic number of Copper $(Cu)$ is $29$.The ground state electronic configuration of $Cu$ is $[Ar] 3d^{10} 4s^1$,which is $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1$.To form the $Cu^{2+}$ ion,two electrons are removed from the neutral $Cu$ atom.First,one electron is removed from the $4s$ orbital,and then one electron is removed from the $3d$ orbital.Therefore,the electronic configuration of $Cu^{2+}$ is $1s^2 2s^2 2p^6 3s^2 3p^6 3d^9$.

$Cu^{2+}$ will have the following electronic configuration:

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