sp^3 hybridized nitrogen is present in | vedclass

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Question

(C) $A)$ Pyridine: The nitrogen atom is $sp^2$ hybridized as it is part of the aromatic ring and has one lone pair in the $sp^2$ orbital.$B)$ Pyrrole:

Vedclass · Accepted Answer

$CH_2 = CH - NH_3^+$

Vedclass · Answer

(C) $A)$ Pyridine: The nitrogen atom is $sp^2$ hybridized as it is part of the aromatic ring and has one lone pair in the $sp^2$ orbital.$B)$ Pyrrole: The nitrogen atom is $sp^2$ hybridized because its lone pair participates in the aromatic sextet of the ring.$C)$ $CH_2 = CH - NH_3^+$: The nitrogen atom is bonded to four atoms (three $H$ atoms and one $C$ atom) with no lone pair,resulting in $sp^3$ hybridization.$D)$ $CH_2 = CH - NH_2$: The nitrogen atom is $sp^2$ hybridized due to conjugation of its lone pair with the adjacent double bond.Therefore,the correct option is $C$.

Molecule	Hybridisation of central atom	Shape
$(a)$ $PCl_5$	$dsp^3$	square pyramidal
$(b)$ $[Ni(CN)_4]^{2-}$	$sp^3$	tetrahedral
$(c)$ $SF_6$	$sp^3d^2$	octahedral
$(d)$ $IF_3$	$dsp^3$	pyramidal

$sp^3$ hybridized nitrogen is present in

Similar Questions

Which of the following molecules has a central atom with $sp^2$ hybridization?

Identify the correct set from the following table:
Molecule Hybridisation of central atom Shape
$(a)$ $PCl_5$ $dsp^3$ square pyramidal
$(b)$ $[Ni(CN)_4]^{2-}$ $sp^3$ tetrahedral
$(c)$ $SF_6$ $sp^3d^2$ octahedral
$(d)$ $IF_3$ $dsp^3$ pyramidal

During the complete combustion of methane $CH_4$,what change in hybridisation does the carbon atom undergo?

$sp^3$ hybridisation is found in

Which type of hybridisation occurs in ethylene?

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