CH_3-CH=O (I) rightleftharpoons CH_2=CH-OH (I | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The stability of tautomers is determined by the bond energies of the functional groups involved.In structure $(I)$,the $C=O$ bond is present,while

Vedclass · Accepted Answer

$I$

Vedclass · Answer

(A) The stability of tautomers is determined by the bond energies of the functional groups involved.In structure $(I)$,the $C=O$ bond is present,while in structure $(II)$,the $C=C$ bond and $O-H$ bond are present.The bond energy of the $C=O$ bond (approx. $745 \ kJ/mol$) is significantly higher than the sum of the bond energies of the $C=C$ bond (approx. $610 \ kJ/mol$) and the $O-H$ bond (approx. $460 \ kJ/mol$) when considering the overall enthalpy of the system.Therefore,the keto form $(I)$ is more stable than the enol form $(II)$.

$CH_3-CH=O$ $(I)$ $\rightleftharpoons$ $CH_2=CH-OH$ $(II)$
Between the two tautomers,which is more stable?

Similar Questions

The total number of stereoisomers possible for the following compound is:

Which of the following statements is not correct about the compound $(I)$ shown below?
$(I)$ = $3-$bromocyclopropene

Which one of the statements about $HOH_2CCH(OH)CHO$ is not correct?

Selected bond angles for six hydrocarbons are shown below. Arrange these hydrocarbons according to their $pK_a$ values,from the lowest to the highest.

How many chiral carbons are there in Reserpine (an antipsychotic drug)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$CH_3-CH=O$ $(I)$ $\rightleftharpoons$ $CH_2=CH-OH$ $(II)$Between the two tautomers,which is more stable?