4-chloro-butan-1-ol + NaOH to (B). The produc | vedclass

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Question

(B) The reaction of $4$-chloro-butan-$1$-ol with $NaOH$ proceeds via an intramolecular nucleophilic substitution reaction. $NaOH$ deprotonates the hyd

Vedclass · Accepted Answer

Tetrahydrofuran

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(B) The reaction of $4$-chloro-butan-$1$-ol with $NaOH$ proceeds via an intramolecular nucleophilic substitution reaction. $NaOH$ deprotonates the hydroxyl group to form an alkoxide ion: $Cl-(CH_2)_4-OH + NaOH 	o Cl-(CH_2)_4-O^-Na^+ + H_2O$. This alkoxide ion then acts as an internal nucleophile,attacking the carbon atom bonded to the chlorine atom (intramolecular $S_N2$ reaction). This leads to the formation of a five-membered cyclic ether,which is tetrahydrofuran.

$4$-chloro-butan-$1$-ol $+ NaOH \to (B)$. The product $(B)$ of the above reaction is:

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