Br-CH_2-CH=CH-CH_2-Br xrightarrow{Zn (dust)} | vedclass

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(D) The reaction of $1,4$-dibromobut$-2-$ene with $Zn$ dust involves the removal of two bromine atoms from the $1$ and $4$ positions.This process is k

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$H_2C=CH-CH=CH_2$

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(D) The reaction of $1,4$-dibromobut$-2-$ene with $Zn$ dust involves the removal of two bromine atoms from the $1$ and $4$ positions.This process is known as $1,4$-elimination.The mechanism involves the formation of a cyclic transition state or an organozinc intermediate,leading to the formation of a conjugated diene.The product formed is $1,3$-butadiene,which has the structure $H_2C=CH-CH=CH_2$.

$Br-CH_2-CH=CH-CH_2-Br \xrightarrow{Zn (dust)} (A)$
Above reaction is an example of $1,4$-elimination. Predict the product.

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$Br-CH_2-CH=CH-CH_2-Br \xrightarrow{Zn (dust)} (A)$Above reaction is an example of $1,4$-elimination. Predict the product.