CH_4 + Cl_2 xrightarrow{hv} CH_3Cl + HClTo ob | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The correct answer is $A$. To maximize the yield of the monohalogenated product $(CH_3Cl)$,the reaction should be carried out with an excess of th

Vedclass · Accepted Answer

high

Vedclass · Answer

(A) The correct answer is $A$. To maximize the yield of the monohalogenated product $(CH_3Cl)$,the reaction should be carried out with an excess of the alkane $(CH_4)$.By keeping the concentration of $CH_4$ high relative to $Cl_2$,the probability of the chlorine radical $(Cl^{\bullet})$ colliding with a $CH_4$ molecule is significantly higher than its collision with a $CH_3Cl$ molecule.If $Cl_2$ were in excess,the chlorine radicals would react with the already formed $CH_3Cl$ to produce polyhalogenated products like $CH_2Cl_2$ via the following steps:$Cl^{\bullet} + CH_3Cl 	o {^{\bullet}}CH_2Cl + HCl$${^{\bullet}}CH_2Cl + Cl_2 	o CH_2Cl_2 + Cl^{\bullet}$Therefore,a high ratio of $CH_4$ to $Cl_2$ is required.

$CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$
To obtain high yields of $CH_3Cl$,the ratio of $CH_4$ to $Cl_2$ must be

Similar Questions

Which of the following has the lowest barrier to rotation about the indicated bond?

$A$ saturated hydrocarbon possesses $2$ carbon atoms and all its hydrogen atoms are of the same type. Provide the structure and the type of hydrogen atoms present.

The number of isomeric products formed by the monochlorination of $2$-methylbutane in the presence of sunlight is . . . . . .

How many isomers are possible for an alkane having molecular formula $C_5H_{12}$?

On cracking petrol,we get

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$To obtain high yields of $CH_3Cl$,the ratio of $CH_4$ to $Cl_2$ must be