$CH_3 - CH = CH_2 \xrightarrow[(2) CH_3CO_2T]{(1) THF : BD_3} (A)$; Product $(A)$ of the above reaction is

  • A
    $CH_3 - CHD - CH_2D$
  • B
    $CH_3 - CHT - CH_2T$
  • C
    $CH_3 - CHD - CH_2T$
  • D
    $CH_3 - CHT - CH_2D$

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Similar Questions

Identify the type of the given reactions:
$(a) \ CH_3CH_2OH \xrightarrow[\Delta]{\text{Conc. } H_2SO_4} CH_2 = CH_2 + H_2O$
$(b) \ CH_2BrCH_2Br + Zn \xrightarrow{\Delta} CH_2 = CH_2 + ZnBr_2$
$(c) \ CH_3CHBr - CH_2Br + Zn \xrightarrow{\Delta} CH_3CH = CH_2 + ZnBr_2$
$(d) \ RC \equiv CR' + H_2 \xrightarrow{Na, \text{liquid } NH_3} RCH = CHR'$
$(e) \ CH_3CH_2Cl + KOH \xrightarrow{\text{ethanol, } KOH} CH_2 = CH_2 + KCl + H_2O$

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Addition of $HCl$ to propene in the presence of peroxides gives:

When $but-1-ene$ is mixed with an excess of bromine,the expected reaction product is:

What is the product formed when $CH_2 = CH(CH_2)_2COOH$ reacts with $HBr$?

Alkenes react with water in the presence of acid as a catalyst to form alcohols: $CH_3-CH=CH_2 + H_2O \xrightarrow{H^{+}} CH_3-CH(OH)-CH_3$. The reaction takes place in accordance with:

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