$CH_3-CH_2-CHO \xrightarrow{Red\,P + HI} A$. Product $A$ is:

The major product formed in the following reaction is:

When the compound $CH_3COCH_2CH_2CH_2CH_2CHO$ undergoes intramolecular aldol condensation,the major product formed is $:$

$OCH-CHO \xrightarrow{OH^{-}} HOCH_2-COO^-$. The reaction given is:

Toluene $\xrightarrow[(2) \ H_3O^{+}]{(1) \ CrO_2Cl_2 / CS_2} X$ $\xrightarrow{\text{Conc. } NaOH} Y + Z$. The correct statements about $Y$ and $Z$ are:
$A. \quad Y$ is a secondary alcohol
$B. \quad Y$ is the reduction product of $X$
$C. \quad Z$ on heating with soda lime gives benzene
$D. \quad Y$ does not give $H_2$ gas with $Na$ metal

$A$ carbonyl compound $X$ $(C_8H_8O)$ undergoes disproportionation with conc. $KOH$ on heating. The product of $X$ with $Zn-Hg/HCl$ is $Y$ and the product of $X$ with $NaBH_4$ is $Z$. What are $Y$ and $Z$ respectively?