Ph-CCl_2-CH_3 xrightarrow{3NaNH_2} text{Produ | vedclass

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(D) The reaction of $Ph-CCl_2-CH_3$ with $2$ equivalents of $NaNH_2$ undergoes dehydrohalogenation to form the alkyne $Ph-C \equiv CH$. Since $3$ equi

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$Ph-C \equiv C^{\Theta} Na^{\oplus}$

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(D) The reaction of $Ph-CCl_2-CH_3$ with $2$ equivalents of $NaNH_2$ undergoes dehydrohalogenation to form the alkyne $Ph-C \equiv CH$. Since $3$ equivalents of $NaNH_2$ are provided,the third equivalent acts as a strong base to abstract the acidic acetylenic proton from $Ph-C \equiv CH$. This results in the formation of the sodium acetylide salt: $Ph-C \equiv C^{\Theta} Na^{\oplus} (A)$.

$Ph-CCl_2-CH_3 \xrightarrow{3NaNH_2} \text{Product } (A)$; Product $(A)$ is

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