$Ph-COOH$ $\xrightarrow{SOCl_2} (A)$ $\xrightarrow{H_2, Pd-BaSO_4} (B)$. Product $(B)$ is:
- A$Ph-CHO$
- B$Ph-CH_2-OH$
- C$Ph-CH_2-Cl$
- D$Ph-CH=CH_2$
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