Ph-CH_3 xrightarrow{CrO_2Cl_2} (A) xrightarro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction sequence is as follows:$1$. $Ph-CH_3$ reacts with $CrO_2Cl_2$ (Etard reaction) to form benzaldehyde $(A)$,which is $Ph-CHO$.$2$. $Ph-

Vedclass · Accepted Answer

$Ph-CO_2^-$

Vedclass · Answer

(B) The reaction sequence is as follows:$1$. $Ph-CH_3$ reacts with $CrO_2Cl_2$ (Etard reaction) to form benzaldehyde $(A)$,which is $Ph-CHO$.$2$. $Ph-CHO$ reacts with concentrated $KOH$ (Cannizzaro reaction). Since benzaldehyde has no $\alpha$-hydrogen,it undergoes disproportionation to form benzyl alcohol $(Ph-CH_2OH)$ and potassium benzoate $(Ph-COO^-K^+)$.$3$. Thus,product $(B)$ is the benzoate ion,$Ph-COO^-$.

$Ph-CH_3$ $\xrightarrow{CrO_2Cl_2} (A)$ $\xrightarrow{conc. KOH} Ph-CH_2OH + (B)$
Product $(B)$ of the above reaction is:

Similar Questions

In the reaction,the product $[X]$ will be:

Identify appropriate reagents for the above reaction.

What is the major product formed when salicylaldehyde is reacted with $2$ equivalents of bromine in glacial acetic acid at $0^{\circ} C$?

Which of the following is the incorrect order for keto-enol stability?

$Ph-CH=CH-CHO + CH_3-CH=CH-CHO \xrightarrow[EtOH, \Delta]{\text{base}} (A) (87\%)$; The product of this reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Ph-CH_3$ $\xrightarrow{CrO_2Cl_2} (A)$ $\xrightarrow{conc. KOH} Ph-CH_2OH + (B)$Product $(B)$ of the above reaction is: