$Ph_2CH-C(=O)H \xrightarrow{\text{aqueous acid}} (A) (81\%) + \text{enol} (2\%) + \text{aldehyde} (17\%)$. Product $(A)$ of the above reaction will be:

  • A
    $Ph_2C=CH-OH$
  • B
    $Ph_2CH-CH_2OH$
  • C
    $Ph_2CH-CH(OH)_2$
  • D
    $Ph_2CH-C(=O)CH_3$

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Assertion : The boiling points of aldehydes and ketones are higher than hydrocarbons and ethers of comparable molecular masses.
Reason : There is a weak molecular association in aldehydes and ketones arising out of the dipole-dipole interactions.

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