underset{C_7H_{14}}{(A)} xrightarrow[Zn/AcOH] | vedclass

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(C) The ozonolysis of an alkene $(A)$ with formula $C_7H_{14}$ yields two products $(B)$ and $(C)$.Given that $(B)$ gives the Cannizzaro reaction,it m

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$(CH_3)_3C-CH=CH-CH_3$

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(C) The ozonolysis of an alkene $(A)$ with formula $C_7H_{14}$ yields two products $(B)$ and $(C)$.Given that $(B)$ gives the Cannizzaro reaction,it must be an aldehyde without an $\alpha$-hydrogen atom.In the structure $(CH_3)_3C-CH=CH-CH_3$,ozonolysis produces $(CH_3)_3C-CHO$ (pivalaldehyde) and $CH_3CHO$ (acetaldehyde).$(CH_3)_3C-CHO$ has no $\alpha$-hydrogen,so it undergoes the Cannizzaro reaction.Also,$(CH_3)_3C-CH=CH-CH_3$ exhibits geometrical isomerism due to the restricted rotation around the $C=C$ double bond.

$\underset{C_7H_{14}}{(A)} \xrightarrow[Zn/AcOH]{O_3} (B) + (C)$
Compound $(A)$ exists as geometrical isomers and $(B)$ gives the Cannizzaro reaction. $(A)$ will be:

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$\underset{C_7H_{14}}{(A)} \xrightarrow[Zn/AcOH]{O_3} (B) + (C)$Compound $(A)$ exists as geometrical isomers and $(B)$ gives the Cannizzaro reaction. $(A)$ will be: