CH_3 - CH = CH - CH_2 - CO_2H xrightarrow[Del | vedclass

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(C) The given reaction is the thermal decarboxylation of a $\beta,\gamma$-unsaturated carboxylic acid. This reaction proceeds via a concerted,six-memb

Vedclass · Accepted Answer

$CH_3 - CH_2 - CH = CH_2$

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(C) The given reaction is the thermal decarboxylation of a $\beta,\gamma$-unsaturated carboxylic acid. This reaction proceeds via a concerted,six-membered cyclic transition state (pericyclic mechanism). During the process,the hydrogen atom from the carboxylic group is transferred to the $\gamma$-carbon,while the $CO_2$ molecule is eliminated and a new double bond is formed between the $\alpha$ and $\beta$ carbons. For the reactant $CH_3 - CH = CH - CH_2 - CO_2H$,the product formed is $CH_3 - CH_2 - CH = CH_2$ (but$-1-$ene). Therefore,the correct option is $C$.

$CH_3 - CH = CH - CH_2 - CO_2H \xrightarrow[\Delta ]{}(X) \,(major)$; Product $(X)$ is

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