The reaction of 4-(text{aminomethyl})text{cyc | vedclass

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(D) The starting material is $4-(	ext{aminomethyl})	ext{cyclohexylmethanol}$,which contains both a primary alcohol $(-CH_2OH)$ and a primary amine $

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(D) The starting material is $4-(	ext{aminomethyl})	ext{cyclohexylmethanol}$,which contains both a primary alcohol $(-CH_2OH)$ and a primary amine $(-CH_2NH_2)$ group.Acetic anhydride $(Ac_2O)$ is an acetylating agent that reacts with both alcohols and amines.However,the reaction with the amine group is generally faster than the reaction with the alcohol group under controlled conditions.In the first step,the more nucleophilic amine group reacts with $Ac_2O$ to form an amide: $R-CH_2NH_2 + Ac_2O ightarrow R-CH_2NHCOCH_3 + CH_3COOH$.This product is $P$,which has an amide group and an intact alcohol group.In the second step,the remaining alcohol group reacts with another equivalent of $Ac_2O$ to form an ester: $R-CH_2OH + Ac_2O ightarrow R-CH_2OCOCH_3 + CH_3COOH$.This product is $Q$,which has both an amide and an ester group.Therefore,$P$ is the amide and $Q$ is the di-acetylated product (amide + ester).

The reaction of $4-(\text{aminomethyl})\text{cyclohexylmethanol}$ with acetic anhydride $(Ac_2O)$ proceeds in two steps to form $P$ and $Q$. Identify $P$ and $Q$ respectively.

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