In the given carbylamine reaction,the value of $x$ (moles of $KOH$ consumed) is:
$C_6H_5NH_2 + CHCl_3 + xKOH \rightarrow C_6H_5NC + 3KCl + 3H_2O$
$C_6H_5NH_2 + CHCl_3 + xKOH \rightarrow C_6H_5NC + 3KCl + 3H_2O$
- A$1$
- B$2$
- C$3$
- D$4$
Explore More
Similar Questions
In the reaction $A$ $\xrightarrow{SnCl_2/HCl} B$ $\xrightarrow{NaNO_2/HCl, 0^{\circ}C} C$ $\xrightarrow{H_2O/\Delta} C_6H_5OH$,what are $A, B$,and $C$?
Difficult
View SolutionEthyl amine on acetylation gives
Medium
View SolutionBenzene diazonium chloride on reaction with aniline in a mild alkaline medium forms:
Compare the basic strengths of the given compounds:
Difficult
View SolutionChoose the correct order of basicity of the following compounds in the aqueous phase:
$(A)$ $(C_2H_5)_2NH$
$(B)$ $C_2H_5NH_2$
$(C)$ $NH_3$
$(D)$ $C_6H_5NH_2$
$(A)$ $(C_2H_5)_2NH$
$(B)$ $C_2H_5NH_2$
$(C)$ $NH_3$
$(D)$ $C_6H_5NH_2$
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo