(B) The central atom $Xe$ in $XeF_2$ has $8$ valence electrons. It forms $2$ sigma bonds with $F$ atoms and has $3$ lone pairs of electrons. Total ele

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The central atom $Xe$ in $XeF_2$ has $8$ valence electrons. It forms $2$ sigma bonds with $F$ atoms and has $3$ lone pairs of electrons. Total electron pairs = $2 \text{ (bond pairs)} + 3 \text{ (lone pairs)} = 5$. For $5$ electron pairs,the hybridisation is $sp^3d$ and the geometry is trigonal bipyramidal.