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(C) For a monoatomic gas,the internal energy $U$ is given by $U = \frac{3}{2} nRT = \frac{3}{2} PV$.Given mass $M = 2\, kg$ and density $\rho = 8\, kg

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$10^4\, J$

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(C) For a monoatomic gas,the internal energy $U$ is given by $U = \frac{3}{2} nRT = \frac{3}{2} PV$.Given mass $M = 2\, kg$ and density $ho = 8\, kg/m^3$,the volume $V$ is $V = \frac{M}{ho} = \frac{2}{8} = 0.25\, m^3$.The pressure $P = 4 	imes 10^4\, N/m^2$.Substituting these values into the energy formula:$U = \frac{3}{2} 	imes (4 	imes 10^4) 	imes 0.25$$U = 1.5 	imes 10^4\, J$.The order of magnitude of the energy is $10^4\, J$.

$2\, kg$ of a monoatomic gas is at a pressure of $4\times10^4\, N/m^2$. The density of the gas is $8\, kg/m^3$. What is the order of energy of the gas due to its thermal motion?

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