The XeF_2 molecule is: | vedclass

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Question

(A) The $XeF_2$ molecule has a central $Xe$ atom with $8$ valence electrons. It forms $2$ bonds with $F$ atoms and has $3$ lone pairs of electrons. Th

Vedclass · Accepted Answer

Linear

Vedclass · Answer

(A) The $XeF_2$ molecule has a central $Xe$ atom with $8$ valence electrons. It forms $2$ bonds with $F$ atoms and has $3$ lone pairs of electrons. The total number of electron pairs is $5$,which corresponds to $sp^3d$ hybridization. According to $VSEPR$ theory,the $3$ lone pairs occupy the equatorial positions to minimize repulsion,resulting in a linear geometry.

List-$I$	List-$II$
$a$. See-Saw Shape	$i$. $XeF_4$
$b$. Square Pyramidal	$ii$. $ClF_3$
$c$. $T$-Shape	$iii$. $PbCl_2$
$d$. Bent Shape	$iv$. $SF_4$
	$v$. $BrF_5$

The $XeF_2$ molecule is:

Similar Questions

Which of the following molecules is linear?

The molecular shapes of $SF_4, CF_4$,and $XeF_4$ are:

What is the structure of $IF_7$?

Match the following:
List-$I$ List-$II$
$a$. See-Saw Shape $i$. $XeF_4$
$b$. Square Pyramidal $ii$. $ClF_3$
$c$. $T$-Shape $iii$. $PbCl_2$
$d$. Bent Shape $iv$. $SF_4$
$v$. $BrF_5$

The correct answer is

The molecules having square pyramidal geometry are

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