BCl_3 is a planar molecule while NCl_3 is pyr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to $VSEPR$ theory,the shape of a molecule is determined by the number of bond pairs and lone pairs around the central atom.$BCl_3$: The

Vedclass · Accepted Answer

$BCl_3$ has no lone pair of electrons but $NCl_3$ has a lone pair of electrons

Vedclass · Answer

(A) According to $VSEPR$ theory,the shape of a molecule is determined by the number of bond pairs and lone pairs around the central atom.$BCl_3$: The central Boron atom has $3$ bond pairs and $0$ lone pairs,resulting in $sp^2$ hybridization and a trigonal planar geometry.$NCl_3$: The central Nitrogen atom has $3$ bond pairs and $1$ lone pair,resulting in $sp^3$ hybridization and a pyramidal geometry due to the repulsion between the lone pair and bond pairs.

$BCl_3$ is a planar molecule while $NCl_3$ is pyramidal,because

Similar Questions

Identify the bond angle $O-S-O$ in the $SO_2$ molecule. (in $^{\circ}$)

The number of lone pairs of electrons on the central atom of $SCl_2$,$O_3$,$ClF_3$,and $SF_6$,respectively,are:

$S +$ Conc. $H_2SO_4 \longrightarrow X + Y$
Here $X$ is a gas and $Y$ is a liquid and both are triatomic molecules. The number of electron lone pairs present on the central atoms of $X$ and $Y$ are respectively.

What information does the $VSEPR$ theory provide about chemically bonded molecules,and what are its limitations?

Which of the following compounds does not have a linear structure?

Vedclass Test Series

Exam Paper Generator

Online Exam Module