For the reaction $Cr_{2}O_{7}^{2-} \xrightarrow{H^{+}} Cr^{3+}$,the equivalent weight of $Cr_{2}O_{7}^{2-}$ is:
- AMolecular weight $/ 6$
- BMolecular weight $/ 3$
- CMolecular weight $/ 4$
- DMolecular weight $/ 2$
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The number of electrons involved in the reduction of permanganate to manganese dioxide in acidic medium is $.......$.
The equivalent weight of $KIO_3$ in the given reaction is ($M=$ molecular mass) :
$2 Cr(OH)_3 + 4 OH^{-} + KIO_3 \rightarrow 2 CrO_4^{2-} + 5 H_2O + KI$
$2 Cr(OH)_3 + 4 OH^{-} + KIO_3 \rightarrow 2 CrO_4^{2-} + 5 H_2O + KI$
In the half-reaction $Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O$,the equivalent weight of $Cr_2O_7^{2-}$ is obtained by dividing its molecular weight by:
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View SolutionFor the given redox reaction: $a MnO_4^{-} + b S_2 O_3^{2-} + H_2 O \longrightarrow x MnO_2 + y SO_4^{2-} + z OH^-$,the values of $a$ and $y$ respectively are:
MediumKCET 2023
View SolutionThe set of coefficients of $P_4$,$OH^{\Theta}$ and $H_2PO_2^{\Theta}$ in the balanced reaction $P_4 + OH^{\Theta} \to PH_3 + H_2PO_2^{\Theta}$ is
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