CO_2 is a non-polar molecule (mu = 0) whereas | vedclass

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(D) $CO_2$ has a linear geometry $(O=C=O)$ due to $sp$ hybridization,where the two bond dipoles cancel each other out,resulting in a net dipole moment

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$CO_2$ is linear whereas $SO_2$ is not linear.

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(D) $CO_2$ has a linear geometry $(O=C=O)$ due to $sp$ hybridization,where the two bond dipoles cancel each other out,resulting in a net dipole moment of $\mu = 0$.$SO_2$ has a bent (angular) geometry due to $sp^2$ hybridization and the presence of a lone pair on the sulfur atom.Because the molecule is not linear,the bond dipoles do not cancel out,resulting in a net dipole moment of $\mu = 1.62 \ D$.Therefore,the difference in polarity is due to the difference in their molecular shapes (geometry).

$CO_2$ is a non-polar molecule $(\mu = 0)$ whereas $SO_2$ is polar $(\mu = 1.62 \ D)$. This difference is due to the fact that:

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