$N_2$ and $O_2$ are converted into monoanions $N_2^-$ and $O_2^-$ respectively. Which of the following statements is wrong?

Assuming $2s-2p$ mixing is $NOT$ operative,the paramagnetic species among the following is:

The number of species from the following which are paramagnetic and with bond order equal to $1$ is:
$H_2, He_2^{+}, O_2^{+}, N_2^{2-}, O_2^{2-}, F_2, Ne_2^{+}, B_2$

The number of antibonding electron pairs in $O_{2}^{2-}$ molecular ion on the basis of molecular orbital theory is (Atomic number of $O$ is $8$)

Among the following species $N_{2}$,$N_{2}^{+}$,$N_{2}^{-}$,$N_{2}^{2-}$,$O_{2}$,$O_{2}^{+}$,$O_{2}^{-}$,$O_{2}^{2-}$,the number of species showing diamagnetism is:

For $F_2$ and $OF$ molecules,consider the following statements:
$(a)$ Bond order for both is one
$(b)$ $OF$ is paramagnetic but $F_2$ is diamagnetic
$(c)$ $F_2$ is more likely to dissociate into atoms than $OF$
$(d)$ Both have greater number of electrons in $BMO$ than that in $ABMO$
Which of the following statements are true $(T)$ or false $(F)$ respectively?