E xleftarrow{KOH/Br_2} D xleftarrow{H_2O_2/OH | vedclass

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(B) $1$. Reaction of $C_2H_5-Cl$ with $NaCN$ gives $C_2H_5CN$ $(C)$.$2$. Partial hydrolysis of $C_2H_5CN$ with $H_2O_2/OH^-$ gives $C_2H_5CONH_2$ $(D)

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Homologue

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(B) $1$. Reaction of $C_2H_5-Cl$ with $NaCN$ gives $C_2H_5CN$ $(C)$.$2$. Partial hydrolysis of $C_2H_5CN$ with $H_2O_2/OH^-$ gives $C_2H_5CONH_2$ $(D)$.$3$. Hofmann bromamide degradation of $C_2H_5CONH_2$ $(D)$ with $KOH/Br_2$ gives $C_2H_5NH_2$ $(E)$.$4$. Reaction of $C_2H_5-Cl$ with $AgCN$ gives $C_2H_5NC$ $(A)$.$5$. Reduction of $C_2H_5NC$ $(A)$ with $LiAlH_4$ gives $C_2H_5NHCH_3$ $(B)$.$6$. $E$ is $C_2H_5NH_2$ (primary amine) and $B$ is $C_2H_5NHCH_3$ (secondary amine).$7$. Both $E$ $(C_2H_7N)$ and $B$ $(C_3H_9N)$ are amines,but they differ by a $-CH_2-$ group,making them homologues.

$E \xleftarrow{KOH/Br_2} D \xleftarrow{H_2O_2/OH^{-} \atop (Partial \ Hydrolysis)} C \xleftarrow{NaCN} C_2H_5-Cl$ $\xrightarrow{AgCN} A$ $\xrightarrow{LiAlH_4} B$
What is the relationship between $B$ and $E$?

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$E \xleftarrow{KOH/Br_2} D \xleftarrow{H_2O_2/OH^{-} \atop (Partial \ Hydrolysis)} C \xleftarrow{NaCN} C_2H_5-Cl$ $\xrightarrow{AgCN} A$ $\xrightarrow{LiAlH_4} B$What is the relationship between $B$ and $E$?