A xrightarrow[1% HgSO_4]{20% H_2SO_4} B xri | vedclass

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Question

(A) The reaction sequence is as follows:$1$. The hydration of an alkyne $A$ in the presence of $HgSO_4$ and $H_2SO_4$ yields a ketone $B$. For phenyla

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Phenylacetylene

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(A) The reaction sequence is as follows:$1$. The hydration of an alkyne $A$ in the presence of $HgSO_4$ and $H_2SO_4$ yields a ketone $B$. For phenylacetylene $(C_6H_5-C \equiv CH)$,hydration follows Markovnikov's rule to give acetophenone $(C_6H_5-CO-CH_3)$ as the product $B$.$2$. Acetophenone $(C_6H_5-CO-CH_3)$ contains a methyl ketone group,which undergoes the iodoform reaction with $I_2$ and $NaOH$ to produce iodoform ($CHI_3$,product $C$) and sodium benzoate $(C_6H_5COONa)$.$3$. Therefore,the reactant $A$ is phenylacetylene.

$A$ $\xrightarrow[1\% \ HgSO_4]{20\% \ H_2SO_4} B$ $\xrightarrow{I_2 + NaOH} C + C_6H_5COONa$. The reactant $A$ is

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