$CH_3-C(CH_3)=CH_2$ $\xrightarrow[R_2O_2]{HBr} X$ $\xrightarrow{CH_3ONa} Y$; $X$ and $Y$ are:

  • A
    $X = CH_3-CH(CH_3)-CH_2-Br$,$Y = CH_3-CH(CH_3)-CH_2-OCH_3$
  • B
    $X = CH_3-C(Br)(CH_3)-CH_3$,$Y = CH_3-C(CH_3)=CH_2$
  • C
    $X = CH_3-CH(CH_3)-CH_2-Br$,$Y = CH_3-C(CH_3)=CH_2$
  • D
    $X = CH_3-C(Br)(CH_3)-CH_3$,$Y = CH_3-C(OCH_3)(CH_3)-CH_3$

Explore More

Similar Questions

What is the difference in reaction of alkene with $HBr$ in the presence of peroxide and in the absence of peroxide?

Arrange the following according to the increasing order of stability: Propene $(I)$,cis-but-$2$-ene $(II)$,trans-but-$2$-ene $(III)$,$2,3$-dimethylbut-$2$-ene $(IV)$,ethene $(V)$.

What are $X$ and $Y$ in the following reaction?
Pent-$2$-ene $\xrightarrow[(ii) Zn / H_2O]{(i) O_3} X + Y$

The final product $B$ of the below reaction sequence is:
$CH_3-CH(Br)-CH_3$ $\xrightarrow{KOH/C_2H_5OH} A$ $\xrightarrow{(C_6H_5CO)_2O_2, HBr} B$

The major product of the reaction of $2-$butene with cold alkaline $KMnO_4$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo