An ionic compound X^{+}Y^{-} has a bcc struct | vedclass

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(A) For a $bcc$ structure, the distance between the nearest ions (which are at the body center and the corner) is given by $d = \frac{\sqrt{3}}{2} a$,

Vedclass · Accepted Answer

$200$

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(A) For a $bcc$ structure, the distance between the nearest ions (which are at the body center and the corner) is given by $d = \frac{\sqrt{3}}{2} a$, where $a$ is the edge length of the unit cell.Given that $d = 1.73 \, \mathring{A} = 173 \, pm$.Substituting the value: $173 = \frac{\sqrt{3}}{2} a$.$a = \frac{173 	imes 2}{\sqrt{3}} = \frac{173 	imes 2}{1.732} \approx 200 \, pm$.Therefore, the edge length of the unit cell is $200 \, pm$.

An ionic compound $X^{+}Y^{-}$ has a $bcc$ structure. The distance between two nearest ions is $1.73 \, \mathring{A}$. What would be the edge length of the unit cell in $pm$?

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