4.4 g of a gas at STP occupies a volume of 2 | vedclass

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(D) At $STP$,$1 \ mole$ of any ideal gas occupies $22.4 \ L$ volume.Given that $2.24 \ L$ of the gas has a mass of $4.4 \ g$.Therefore,$22.4 \ L$ of t

Vedclass · Accepted Answer

$CO_2$

Vedclass · Answer

(D) At $STP$,$1 \ mole$ of any ideal gas occupies $22.4 \ L$ volume.Given that $2.24 \ L$ of the gas has a mass of $4.4 \ g$.Therefore,$22.4 \ L$ of the gas will have a mass of $\frac{4.4}{2.24} 	imes 22.4 = 44 \ g$.The molar mass of the gas is $44 \ g/mol$.Comparing this with the molar masses of the options:$O_2 = 32 \ g/mol$$CO = 28 \ g/mol$$NO_2 = 46 \ g/mol$$CO_2 = 44 \ g/mol$Thus,the gas is $CO_2$.

$4.4 \ g$ of a gas at $STP$ occupies a volume of $2.24 \ L$. The gas can be:

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