(B) The chemical reaction is: $2NH_3 + 3CuO \to N_2 + 3H_2O + 3Cu$ In this reaction,the oxidation state of nitrogen changes from $-3$ in $NH_3$ to $0$

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(B) The chemical reaction is: $2NH_3 + 3CuO \to N_2 + 3H_2O + 3Cu$ In this reaction,the oxidation state of nitrogen changes from $-3$ in $NH_3$ to $0$ in $N_2$. The change in oxidation state per nitrogen atom is $0 - (-3) = +3$. Therefore,each nitrogen atom in the ammonia molecule loses $3$ electrons.