An acidified solution of sodium thiosulfate i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The structure of the thiosulfate ion $(S_2O_3^{2-})$ consists of a central sulfur atom bonded to three oxygen atoms and one terminal sulfur atom.

Vedclass · Accepted Answer

two sulfur atoms are in different oxidation states of $+6$ and $-2$.

Vedclass · Answer

(B) The structure of the thiosulfate ion $(S_2O_3^{2-})$ consists of a central sulfur atom bonded to three oxygen atoms and one terminal sulfur atom. In this structure,the central sulfur atom is in the $+6$ oxidation state,while the terminal sulfur atom is in the $-2$ oxidation state. Due to this disproportionation tendency and the presence of these distinct oxidation states,the acidified solution is unstable and tends to decompose into sulfur and sulfur dioxide.

An acidified solution of sodium thiosulfate is unstable because in thiosulfate,the two sulfur atoms are in:

Similar Questions

Oxidation number of $P$ in $Mg_2P_2O_7$ is

Oxidation number of Nitrogen in $NH_4NO_3$ is

What is the oxidation number of $Mn$ in $MnO_4^{-}$?

What are the oxidation states of $S$ in $S_8$,$H_2S$,and $S_2F_2$ respectively?

The oxidation states of nitrogen in $NO$,$NO_{2}$,$N_{2}O$ and $NO_{3}^{-}$ are in the order of :

Vedclass Test Series

Exam Paper Generator

Online Exam Module